Figuring out why these numbers are the way they are takes a fair amount of work. Therefore oxidation number of Pb is +2. But Sulfate ion has -2 charge. Could you tell me how you went about getting the oxidation number for Pb in PbSO4? The anodic oxidation of solid Pb in H 2 SO 4 to form PbSO 4 has been investigated by rotating disc, potentiostatic pulse and ac impedance measurements. In order to make the compound neutral, Pb must be +2. Sulfide ion is at -2 oxidation state. The system is compared with measurements on Pb(Hg) in H 2 SO 4 and with Pb(Hg), Hg, solid Pb in HClO 4 solution. Asked by | 25th Mar, 2009, 06:56: PM. Oxidation number of Pb is +2 If you consider oxidation as the loss of electrons and gain of oxidation number, and reduction as the gain of electrons and decrease in oxidation number, the oxidation states are as follows: Pb : 0 (Elementary state) H in H2SO4 : +2. PbSO4 --> Pb2+ + SO4 2- (A net dissociation reaction of the salt) SO4 has an oxidation number of -2. Sum of all oxidation number =0. what is the oxidation number of pb in pbso4. Identify the substance oxidised, reduced, oxidising agent and reducing agent for each of the following reactions: Pb(s) + PbO 2 (s) + 2H 2 SO 4 (aq) â 2PbSO 4 (s) + 2H 2 O(l) +1 +3 0-1 +2 +1. How to calculate oxidation number of Pb in PbSO4?And Explain? ... Pb PbO2 PbSO4 H2O H2SO4. Identify the products and the reactants, and then their oxidation numbers. Check to see if the oxidation numbers show oxidation or reduction. The total should equal when you add all oxidation numbers: Pb + (-2) = 0 ----> Pb = +2. Oxidation number of O=-2. What is the oxidation number of phosphorous in the H3PO2 molecule? You are correct that oxidation is the loss of electrons and reduction is the gaining of electrons. To neutral that -2 charge, +2 charge should be there and it is given by Pb 2+ ion. I went by the rule of the most electronegative atom getting their typical oxidation state (so O was assigned -2 (total -8)...then S was assigned -2...and finally Pb was given +10 to balance the molecule). The rates of PbSO4 formation on the Pbâ0.08 mass% CaâSn alloys, which are the choice materials for grids in the valve-regulated leadâacid battery (VRLA), were inhibited by the presence of Sn. Therefore oxidation number of Pb in PbSO 4 ⦠Also, the answer would not be +10 if what you had said was correct (about the sulfur ion). H2O2 + PbS --> PbSO4 + H2O. Identify which reactants are being oxidized (the oxidation number increases when it reacts) and which are being reduced (the oxidation number goes down). pb +2 s-2 + h +1 2 o-1 2 â pb +2 s +6 o-2 4 + h +1 2 o-2 b) Identify and write out all redox couples in reaction. Expert Answer: Let the oxidation number of Pb=x. Oxidation = number goes down Reduction = number goes up. Therefore x+6-8=0. 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