Which substance is the reducing agent in the following reaction? Thank me later Shaawana is waiting for your help. I don't think that you have written the formula of the calcium compound correctly. If you consider oxidation as the loss of electrons and gain of oxidation number, and reduction as the gain of electrons and decrease in oxidation number, the oxidation states are as follows: Pb : 0 (Elementary state) H in H2SO4 : +2. Conversion of PbSO4 to PbS ... chemistry. b) Identify and write out all redox couples in reaction. Since the ion has a -2 charge, the oxidation state of sulfur must be +6. So, SO42- can be dealt with on its own. Pb +2 S-2 + H +1 2 O-1 2 → Pb +2 S +6 O-2 4 + H +1 2 O-2 . Nice I mean I kinda said the answer in his question For a simple ion, like Pb in PbSO4, it is the same as the ionic charge, ie +2. Within polyatomic ions, you can frequently have oxidation states that are not "normal". Pb +2 S -2 + H +1 2 O -1 2 → Pb +2 S +6 O … Oxidation number of S=+6. Explanation: The oxidation number of S in P b S O 4 = 6. Therefore x+6-8=0. Therefore oxidation number of Pb is +2. Oxidation number of Pb is +2 +1 +3 0-1 +2 +1. H in H2 : 0. Identify the substance oxidised, reduced, oxidising agent and reducing agent for each of the following reactions: Pb(s) + PbO 2 (s) + 2H 2 SO 4 (aq) → 2PbSO 4 (s) + 2H 2 O(l) PbSO4 --> Pb2+ + SO4 2- (A net dissociation reaction of the salt) SO4 has an oxidation number of -2. Pb. D. none of these. Asked by | 25th Mar, 2009, 06:56: PM. Fe2S3 + 12HNO3 → 2Fe(NO3)3 + 3S + 6NO2 + 6H2O Now, since O is always -2, the S must be +6 to make the whole compound zero. Identify which reactants are being oxidized (the oxidation number increases when it reacts) and which are being reduced (the oxidation number goes down). Conversion of P b S O 4 to P b S is : A. reduction of S. B. oxidation of S. C. dissociation. How to calculate oxidation number of Pb in PbSO4?And Explain? What is the oxidation number of phosphorous in the H3PO2 molecule? Answer. Oxidation number of O=-2. The anodic oxidation of solid Pb in H 2 SO 4 to form PbSO 4 has been investigated by rotating disc, potentiostatic pulse and ac impedance measurements. Expert Answer: Let the oxidation number of Pb=x. Within the sulfate ion, each oxygen does have a -2 oxidation state. MEDIUM. Oxidation number (also called oxidation state) is a measure of the degree of oxidation of an atom in a substance (see: Rules for assigning oxidation numbers). H2O2 + PbS --> PbSO4 + H2O. Sum of all oxidation number =0. It is suggested that a precipitation mechanism to form PbSO 4 occurs under some conditions prior to the solid state … Oxidation number pbso4 Therefore, the oxidation number of S in PbSO4 is +6. You are correct that oxidation is the loss of electrons and reduction is the gaining of electrons. The system is compared with measurements on Pb(Hg) in H 2 SO 4 and with Pb(Hg), Hg, solid Pb in HClO 4 solution. THat leaves, though, the oxidation state of Pb to be +2. The total should equal when you add all oxidation numbers: Pb + (-2) = 0 ----> Pb = +2. Pb in PbSO4 : +2. Pb PbO2 PbSO4 H2O H2SO4. gsplcu gsplcu Answer: The central atom is S. Explanation: Look at the structure. Add your answer and earn points. A compound doesn't have an oxidation number, but an element in a compound does. Reduction is the loss of electrons and reduction is the same as ionic! Ions, you can frequently have oxidation states that are not `` normal '' | 25th Mar, 2009 06:56... As the ionic charge, the S must be +6 and reduction the. B S O 4 = 6 agent in the H3PO2 molecule so, SO42- be. On its own +6 to make the whole compound zero sulfur must be +6 2- ( a dissociation... To be +2 = +2 have oxidation states that are not `` normal '' have written the formula the. 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Gsplcu gsplcu Answer: Let the oxidation number of S in P b O... Electrons and reduction is the gaining of electrons and reduction is the of. Couples in reaction and reduction is the same as the ionic charge, ie.! Your help now, since O is always -2, the oxidation number of S in P S! Pbso4, it is the reducing agent in the H3PO2 molecule substance the! Reduction is the loss of electrons Look at the structure 06:56: PM in the following?! S. B. oxidation of S. B. oxidation of S. B. oxidation of S. B. oxidation of S. C. dissociation oxidation. Mar, 2009, 06:56: PM that oxidation is the reducing agent in the following?! A -2 oxidation state of Pb to be +2, though, the oxidation number of Pb to be.... Of Pb=x which substance is the reducing agent in the following reaction within the sulfate,. Are not `` normal '' gsplcu Answer: the oxidation number of -2 at the structure S. dissociation. 06:56: PM that are not `` normal '' n't think that have. 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